t^2-20t+150=0

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Solution for t^2-20t+150=0 equation: 



t^2-20t+150=0

a = 1; b = -20; c = +150;
Δ = b2-4ac
Δ = -202-4·1·150
Δ = -200
Delta is less than zero, so there is no solution for the equation

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